Math, asked by shlokverma969, 4 months ago

∆ ABC ∆ RSM and if AB =10, BC=12,RS= 5 find SM​

Answers

Answered by harshkardile14
1

Answer:

Given :-

∆ ABC ,∆ RSM and if AB =10, BC=12,RS= 5.

To find :- SM.

Solution :-

∆ ABC ~ ∆ RSM ........(Similar triangles)

AB BC AC

---- = ----- = ------ ...........(Property of similar ∆ )

RS SM RM

10 12

---- = -----

5 SM

10SM = 60

SM = 6.

Answer :- SM = 6.

Answered by amitnrw
2

Given : ∆ ABC ≈  ∆RSM

AB =10, BC=12,RS= 5

To Find : SM

Solution:

∆ ABC ≈  ∆RSM

corresponding sides of similar triangles are in same proportion

Hence

AB/RS  = BC/SM  = AC/RM

AB/RS = BC/ SM

=> 10/5  = 12 /SM

=> 2 = 12/SM

=> SM = 12/2

=> SM = 6

Length of SM = 6

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