Question

ΔABC Δs a right angled triangle at A and AD is the altitude to side BC if AB = 8 cm and AC = 15 cm then BC = ?

Answer 1

Answer:

17cm

Step-by-step explanation:

By Pythagorean theorem

BC^2 = AB^2 + AC^2

BC^2=8^2+15^2

BC^2= 64 +225

BC=√289

BC=17

Answer 2

By Pythagoras theorem ,

AC² = AB²+BC²

(15)²=(8)²+BC²

BC²=(15)²-(8)²

BC²=225-64

BC²=261

BC=root 261