∆ABC similarly to ∆PQR , AB:PQ =5:8 then find the value of BC and QR.
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Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴
A(△ABC)
A(△PQR)
=
AB×BC
PQ×QR
=
5×9
6×10
=
3
4
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