ABC such that ZADC= _BAC. Show
13. Dis a point on the side BC of a triangle
that CA=CB.CD
14. Sid
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I am not fake but I am broken
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In △ADC and △BAC
∠ADC=∠BAC (Given)
∠C is Common
∴ by AA Criterion of Similarity, △ADC ∼ △BAC
⇒BAAD=ACDC=BCAC
⇒ACDC=BCAC
∴ CA2=CB.CD
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