∆ABC, tan (A-B)/2 tan c/2 =?
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2
Step-by-step explanation:
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Answered by
2
Answer:
Step-by-step explanation:
(a+b)/2=90* -c/2
so tan[(a+b)/2]=tan(90*-c/2)=cot(c/2) but
cot(c/2)=1/tan(c/2) so
tan[(a+b)/2]=1/tan(c/2) so
tan[(a+b)/2].tan(c/2)=1
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