Question

∆ abc ~ to ∆RQP angle A=80 °& angle B=60° what is the value of angle p

Answer 1

triangle ABC is congruent to triangle rqp so the angle p will be equal to c
So c=p=40°

Answer 2

<A +<B +<C= 180° (A.S.P.)

80°+60°+<C=180°

<C=180°-140°

<C=40°

since ABC~PQR

<P=<C

<P=40°