ABC us a triangle in which OB, OC bisects the angle ABC, ACB respectively. if AB is greater than AC prove that OB is greater than OC
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OB > OC if AB > AC & OB and OC are the bisectors of Angle B and angle C respectively
Step-by-step explanation:
AB > AC
in a triangle angle opposite to sides of triangle are in same order as side
Hence
∠C > ∠B
OB & OC are bisector of ∠B & ∠C
=> ∠OCB > ∠OBC
∠OCB is opposite to OB
∠OBC is opposite to OC
=> OB > OC
Step-by-step explanation:
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