ABC us an isosceles triangle with AB=ac draw ap perpendicular bc to show that angel b = angle c
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Step-by-step explanation:
In triangle ABC, with AP perpendicular BC
so,
In triangle APB and triangle APC
<APB = <APC = 90°
AB = AC (common)
AP = AP (given)
therefore,
triangle APB ~= triangle APC
by RHS concurrency
by CPCT
<B = <C
Hence Proved.
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