∆ABC ~ ∆XYZ ,9xA(∆XYZ)=16xA(ABC) .if YZ=20 then find BC.
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Given that ΔABC and Δxyz are equilateral triangles.
i.e., AB=BC=CA
and
XY=YZ=ZX …………….(1)
and
here AB=XY ………………(2)
By equation (1) & (2)
BC=YZ and CA=ZX …………….(3)
We have to show that
ΔABC=ΔXYZ
In ΔABC and Δxyz
AB=XY (Given)
BC=YZ (by equation (2))
CA=ZX (by equation (3))
ΔABC=Δxyz(By sss rules).
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