∆ABC~ ∆XYZ , ABC =16, XYZ = 25, AB = 4 then Find XY
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Given :- ∆ABC~ ∆XYZ , Ar(ABC) = 16, Ar(XYZ) = 25, AB = 4 then Find XY ?
Solution :-
we know that, when two ∆'s are congruent ,
- Ratio of area of ∆'s = Ratio of square of their corresponding sides .
given that,
→ ∆ABC ~ ∆XYZ .
so,
→ A(∆ABC) : A(∆XYZ) = AB² : XY²
→ A(∆ABC) / A(∆XYZ) = AB² / XY²
→ 16 / 25 = AB² / XY²
→ 4² / 5² = AB² / DE²
→ AB / XY = 4/5
→ 4/XY = 4/5
→ XY = 5 (Ans.)
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