Question

∆ABC ~ ∆xYz. if ar(∆ABC) = 25sq.cm and ar(∆xyz) = 64sq.cm,
then BC/yz =
​

Answer 1

Sorry idk...................

Answer 2

Answer:

∆ABC~∆XYZ.

ar(∆ABC) =25sq.cm

ar(∆XYZ) =64sq.cm

the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

therefore ar(∆ABC) /ar(∆XYZ) =[BC/YZ] sq.

[25/64]=[BC/YZ]sq

[5/8]=[BC/YZ]