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ABCandDBCare two isosceles triangles on the same base BC .shw that​

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Answered by nisharn422
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Congruence of Triangles

Criteria for Triangle Congruence

ABC and DBC are two isosce...

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Asked on October 15, 2019 bySupraja Maddela

△ABC and △DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that

(i) △ABD≅△ACD

(ii) △ABP≅△ACP

(iii) AP bisects ∠A as well as △D.

(iv) AP is the perpendicular bisector of BC.

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VIDEO EXPLANATION

ANSWER

(i) In △ABD and △ACD, 

AB=AC         ....(since △ABC is isosceles) 

AD=AD        ....(common side)

BD=DC        ....(since △BDC is isosceles) 

ΔABD≅ΔACD     .....SSS test of congruence, 

∴∠BAD=∠CAD i.e. ∠BAP=∠PAC          .....[c.a.c.t]......(i)

(ii) In △ABP and △ACP, 

AB=AC          ...(since △ABC is isosceles)

AP=AP         ...(common side)

∠BAP=∠PAC      ....from (i)

△ABP≅△ACP    .... SAS test of congruence

∴BP=PC      ...[c.s.c.t].....(ii)

∠APB=∠APC     ....c.a.c.t.

(iii) Since 

Answered by trupti59
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Answer:

the answer above is correct

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