ABCandDBCare two isosceles triangles on the same base BC .shw that
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7th
Maths
Congruence of Triangles
Criteria for Triangle Congruence
ABC and DBC are two isosce...
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Asked on October 15, 2019 bySupraja Maddela
△ABC and △DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that
(i) △ABD≅△ACD
(ii) △ABP≅△ACP
(iii) AP bisects ∠A as well as △D.
(iv) AP is the perpendicular bisector of BC.

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(i) In △ABD and △ACD,
AB=AC ....(since △ABC is isosceles)
AD=AD ....(common side)
BD=DC ....(since △BDC is isosceles)
ΔABD≅ΔACD .....SSS test of congruence,
∴∠BAD=∠CAD i.e. ∠BAP=∠PAC .....[c.a.c.t]......(i)
(ii) In △ABP and △ACP,
AB=AC ...(since △ABC is isosceles)
AP=AP ...(common side)
∠BAP=∠PAC ....from (i)
△ABP≅△ACP .... SAS test of congruence
∴BP=PC ...[c.s.c.t].....(ii)
∠APB=∠APC ....c.a.c.t.
(iii) Since
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