Question

Abcd 8s a cyclic quadrilateral O is the centre of the circle if angle bod on arc bcd is 140°then angle bcd is​

Answer 1

Answer:

)∠ACB=21∠AOBbisectors=21×(3600−1400)=21×220=1100(2)∠OBC=3600−(∠AOB+∠OAC+∠ACB)=3600−(1400+50o+1100)=3600−3000=600(3)since,OA&OBisradius∴ΔOABisisoscelesΔ∴∠OAB=21(1800−1400)=21×400=200(4)∠CBA−∠OBC−∠OBA=∠OBC−∠OAB[ΔOABisisoscelesΔ]=60

Step-by-step explanation:

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