ABCD a parallelogsam Diagonals
meet at O i BD =10cm. and Ac=12.cm
The value of a x is
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AC=12cm
BD=16cm
AreaofΔPAB=
s(s−a)(s−b)(s−c)
= 12(12−6)(12−8)(12−10)=
12×6×4×2= 576 =24cm 2
AreaofΔPAB= 21 ×PQ×AB
PQ= 10
24×2 =4.8cm
∴AE=2PQ=2×4.8=9.6cm
AreaofrectangleABCD=10×9.6=96cm
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