Question

ABCD
ABCD is a rhombus whose diagonals intersect at O
at O. Show that AOB =~COD
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Answer 1

GIVEN:- ABCD is a rhombus

To show:- AOB=COD

SOLVE:-

in ∆AOB & ∆COD,

BAO=OCD (alt. angles)

AB=CD (sides are equal of rhombus)

ABO=ODC (alt. angles)

∆AOB is congruent to ∆COD by ASA rule.

AOB=COD by CPCT.