ABCD an isosceles trapezium its parallel side measure 13 cm and 35 cm its non parallel sides are equal and measure 10 centimetre find the area of the trapezium
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S O L U T I O N : (Ques. Error)
ABCD is an isosceles trapezium it's parallel side measure 13 cm & 25 cm, it's non - parallel sides are equal & measure 10 cm .
Firstly, attachment a figure of Isosceles trapezium according to the question.
As we know that formula of the area of trapezium;
A/q
We have,
- AB = 13 cm
- FC = 25 cm
- AF = 10 cm
- BC = 10 cm
So, ED = FC - AB
→ ED = 25 cm - 13 cm
→ ED = 12 cm
Therefore it's isosceles trapezium, so 2FE = ED
→ 2 FE = 12
→ FE = 12/2
→ FE = 6 cm
Now,
Now,
Thus,
The area of the trapezium will be 152 cm² .
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