ABCD and AGFE are two parallelogram with equal areas show that DG parallel FC
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Point A is common to both the parallelograms
both the parallelograms have equal area(base*height)
now if a transverse cut two parallel lines their alternate angles are equal
Join GD and FC
angle(GDA)=angle(DAC)
which are alternate angles and AD is transverse to the lines GD and FC
=>GD is parallel to FC
proved
both the parallelograms have equal area(base*height)
now if a transverse cut two parallel lines their alternate angles are equal
Join GD and FC
angle(GDA)=angle(DAC)
which are alternate angles and AD is transverse to the lines GD and FC
=>GD is parallel to FC
proved
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