ABCD and PQRC are rectangles and Q us the mid-point of AC show that P is the mid-point of DC and R is the mid- point of BC.also, find the ratio of ar(ABCD) and ar(PQRC)
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l=a;b=b
diagonal=c
area of ABCD=ab
(a/2)^2+x^2=(c/2)^2
x=√(c^2-a^2)/2
area of PQRC=a/2*√(c^2-a^2)/2
ratio=4ab/a√(c^2-a^2)
diagonal=c
area of ABCD=ab
(a/2)^2+x^2=(c/2)^2
x=√(c^2-a^2)/2
area of PQRC=a/2*√(c^2-a^2)/2
ratio=4ab/a√(c^2-a^2)
sachinsahani:
please give me answer in detail
x=PQ to find x apply Pythagorean theorem, we know that hypotenuse is half of the diagonal of ABCD
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