Question

ABCD + EFGB= EFCBH determine the values of all
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Answer 1

Answer: The values of all the alphabet are as follows-

A= 9, B = 1, C=1, D=1, E=1, F=0, G=0, H=1

Step-by-step explanation:

Since there are no restrictions on selecting the values and it is an open-ended question with no condition, we can repeat the numbers.

Therefore, ABCD + EFGB= EFCBH can be satisfied by the following values of the Alphabets,

     A= 9, B = 1, C=1, D=1, E=1, F=0, G=0, H=1

Now we put all the values in the condition,

         = 9110 + 1001 ⇒ 10111

Hence, the condition is verified.

Therefore, the values of all correspondent alphabets equal to

  A= 9, B = 1, C=1, D=1, E=1, F=0, G=0, H=1

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Answer 2

A= 9, B = 1, C=1, D=1, E=1, F=0, G=0, H=1

Explanation :

We can repeat the numbers because there are no constraints on selecting the figures and it is an open-ended question with no conditions.

As a result, the values of the Alphabets ABCD + EFGB= EFCBH can be met by:

A=9, B=1, C=1, D=1, E=1, F=0, G=0, H=1

We've now added all of the values to the condition.

$= 9100 + 1001$ ⇒ $10111$

Hence, the condition is confirmed.

As a result, all correspondent alphabets have the same value.

A=9, B=1, C=1, D=1, E=1, F=0, G=0, H=1.

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