Math, asked by ro7usbarushmedha, 1 year ago

ABCD ia parallelogram and APQ is a straight line meeting BC at P and DC produced at Q. Prove that the rectangle obtained by BP and DQis equal to the rectangle contained by AB and BC.

Answers

Answered by kvnmurty
151
The diagram shows parallelogram ABCD and the line APQ.

ΔABP and ΔCQP are similar, as the corresponding sides are parallel. Hence, their ratios: 

             CQ / AB = PQ / AP = CP / BP
As AB = CD,  Adding 1 to each of the above ratios, we get  
        (CD+CQ) / AB  = (PQ + AP) / AP = (CP + BP) / BP
         DQ / AB = AQ / AP = BC / BP

=>  BP * DQ  =  AB * BC 
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kvnmurty: clik on thanks. select best ans
Answered by agarwalsunita295
23

Answer:

Step-by-step explanation:

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