Question

ABCD in which AB=6cm, BC=5cm, <A=55,<B=110and<D=90 answer plz tell me the answer its very urgent​

Answer 1

Answer:hi dear this is your answer

Step-by-step explanation:

"Given: AB = 6 cm, BC = 5cm, angle A = 55 degree, angle B = 110 degree and angle D = 90 degree.

Steps;

Angle sum property of a quadrilateral:

∠A + ∠B + ∠C + ∠D = 360 degree

55 + 110 + ∠C + 90 = 360 degree

∠C = 105 degree

1. Draw AB = 6 cm.

2. Take A as a centre construct an angle of 55 degrees and then from B make 110 degrees.

3. Take the measurement of BC = 5cm on the compass and cut the angle 110 line. Mark the point as C.

4. Now take C as a centre and construct 105 degrees.

5. The point where angle C and D will meet will be D.

Answer 2

Step-by-step explanation:

⇒ Draw a line segment AB = 6cm.

⇒ Construct an angle of 60

∘

at point B.

⇒ Cut off BC = 4cm.

⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120

∘

at point A and C which meet at point D.

⇒ Thus, ABCD is a required parallelogram.

⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )

⇒ Perimeter of parallelogram ABCD=2(a+b)

⇒ 2(6+4) [From( 1 )]

∴ Perimeter of parallelogram ABCD=20cm.