ABCD in which side ab is equal to 4 cm and diagonal AC is equal to 6.4 cm find the Rhombus perimeter .
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1
Answer:
Steps of Construction:
(i) Draw AC=6.4 cm.
(ii) Bisect AC at O.
(iii) Make ∠COX=60
o
and produce XO to Y.
(iv) Set off OB=
2
1
(8.2)=4.1cm and OD=
2
1
(8.2)=4.1cm as shown.
(v) Join AB,BC,CD and DA.
Then, ABCD is the required parallelogram.
Measure the sides of the parallelogram. The sides are of length 3.7 cm and 6.3 cm. Therefore, perimeter =2(3.7+6.3)=20 cm
Step-by-step explanation:
Answered by
0
The perimeter of Rhombus
= 5×4= 20cm
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