Question

ABCD IOS A SQUARE ,X AND Y ARE POINTS ON SIDES AD AND BC RESPECTIVELY SUCH THAT AY=BX. PROVE THAT BY=AX AND ANGLE BAY=ANGLE ABX

Answer 1

in triangle aby and triangle abx
angle xab=angle yab sqaure so angle are 90
xb=ay given
ab is common
both triangles are congurent by sas
by=ax
angle bay=angle abx by cpct