Question

ABCD is a circle Quadrilateral . ∠A:∠B:∠C=3:4:5 then ∠A:∠D ?

plz friends give me the answer, tommorow my exam..​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

in a cyclic quadrilateral ABCD angle A: angle C = 4 : 5 and Angle B : angle D = 5 : 7 then find all the angles of ABCD

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

Hence,B=5*15=75

and.C=7*15=105

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

let the angles A=4x and C=5x

so in a cyclic quadrilateral opposite angles =180

so A+C=180

4x+5x=180

9x=180

x=180/9

x=20

Hence A=4*20=80

C=5*20=100

Similarly,

B=5x

C=7x

So.B+C=180

5x+7x=180

12x=180

x=180/12

x=15

Hence,B=5*15=75

and.C=7*15=105

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

Answer 2

Answer:

let the angles A=4x and C=5x

so in a cyclic quadrilateral opposite angles =180

so A+C=180

4x+5x=180

9x=180

x=180/9

x=20

Hence A=4*20=80

C=5*20=100

Similarly,

B=5x

C=7x

So.B+C=180

5x+7x=180

12x=180

x=180/12

x=15

Hence,B=5*15=75

and.C=7*15=105