Math, asked by shreemanpabitra, 4 days ago

ABCD is a circular quadrilateral AB = 4 cm. BC = 6 cm. AD = 8 cm. , CD = 6 cm. , AC = 10 cm. However BD = __ cm.
BD=​

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Answered by kdeiva2020
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Class 8

>>Maths

>>Practical Geometry

>>Construction of Quadrilaterals

>>Construct a quadrilateral ABCD with AB =

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Construct a quadrilateral ABCD with AB=6 cm,BC=4 cm,CD=7 cm,AC=8 cm and BD=7 cm.

⇒ Draw a line segment AB=6cm.

⇒ With B as a center and radius BC=4cm, draw an arc.

⇒ With A as a center and radius AC=8cm, draw an arc intersecting the previous arc at point C.

⇒ Again take B as a center and radius BD=7cm, draw an arc.

⇒ With C as a center and radius CD=7cm, draw an arc intersecting the previous arc at point $$D$4.

⇒ Join AC,BC,BD,CDandAD.

Thus, ABCD is a required quadrilateral

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