Math, asked by raj4876, 5 months ago

ABCD is a convex quadrilateral. AC and
BD intersect each other at O such that
ACI BD. Eis a point on BD such that
AE and CE bisect ZBAD and BCD
respectively. If LABD = 50°, ZADB =
30°, 2CBD = 70° and LADC = 70°, then
ABCD एक उत्तल चतुर्भुज है। ACव BD एक दूसरे को 0
पर प्रतिच्छेद करते हैं जबकि ACLBD है। E, BD पर एक
बिन्दु हैं जबकि AEव CEक्रमश: ZBAD व LBCD को
fusta od žluf LABD = 50°, LADB = 30°,
2CBD = 70° JYT LADC = 70',​

Answers

Answered by aminusadath49
0

Answer:

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