◼ABCD is a cyclic
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0
ABCD IS cyclic quad.
A + C =180
7y-21=4y+3
7y-4y=3+21
3y=24
y=8
therefore
A=7(8)-21=35
A + C =180
7y-21=4y+3
7y-4y=3+21
3y=24
y=8
therefore
A=7(8)-21=35
Answered by
2
A+C=180°.........(by cyclic quadrilateral
theorem)
7y-21+4y+3=180°
11y-18=180°
11y=180+18
11y=198
y=198/11
y=18
therefore
A=7y-23
A=7×18-23
A=136-23
A=113°
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theorem)
7y-21+4y+3=180°
11y-18=180°
11y=180+18
11y=198
y=198/11
y=18
therefore
A=7y-23
A=7×18-23
A=136-23
A=113°
_____
hope it helps u^_^ ^_^ ^_^
plzz mark it as brainliest
X____X
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