Math, asked by ridhimakhatri2005, 4 months ago

ABCD is a cyclic parallelogram. Find BD if AC is 13 cm.

sajshet: We know that, diagonals in a rhombus bisect each other perpendicularly.
Let O is the intersecting point of diagonals AC and BD.
OA=
2
AC

=
2
24

=12cm

OB=
2
BD

=
2
10

=5cm
Now, in △AOB,∠AOB=90
o

⇒ (AB)
2
=(OA)
2
+(OB)
2
[ By Pythagoras theorem ]
⇒ (AB)
2
=(12)
2
+(5)
2

⇒ (AB)
2
=144+25
⇒ (AB)
2
=169
∴ AB=13cm
We know that, all sides of rhombus are equal.

sajshet: hope it helpful

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ABCD is a cyclic parallelogram. Find BD if AC is 13 cm.