ABCD is a cyclic quadrilateral and AB is diameter and angle D is 130. find X
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1
Answer:Therefore X=40
Step-by-step explanation:
Draw a line joining A and C.
therefore,∠ACB=90 (angle subtended by the diameter of circle)
and ∠ABC is the supplementary angle of ∠ADC. (opposite angles of cyclic quadrilateral)
∴∠ABC=180−∠ADC=180−130=50
∠BAC=180−(∠ACB+∠ABC)
=180−50−90=40
Answered by
1
Answer:
here is your answer :
Step-by-step explanation:
∠ACB=90
∴∠ABC=180−∠ADC=180−130=50
∠BAC=180−(∠ACB+∠ABC)
=180−50−90=40
I think your ques would be to find angle angle bac
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