Math, asked by roshinipriya668, 8 months ago

ABCD is a cyclic quadrilateral DA = 4x and DC =2x then the value of x ​

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Answered by Walterjr
2

In a cyclic quadrilateral ABCD,∠A=(2x+4)

o

,∠B=(y+3)

o

,∠C=(2y+10)

o

and∠D=(4x−5)

o

. Find measure of each angle.

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ANSWER

∠A+∠C=180

o

[ Sum of angles in cyclic quadrilateral are supplementary ]

⇒ 2x+4

o

+2y+10

o

=180

o

⇒ 2x+2y=166

o

∴ x+y=83

o

----- ( 1 )

Now, ∠B+∠D=180

o

⇒ y+3

o

+4x−5

o

=180

o

⇒ 4x+y=182

o

---- ( 2 )

Subtracting equation ( 1 ) from equation ( 2 ) we get,

x=33

o

Substituting value of x in equation ( 1 ) we get,

y=50

o

.

⇒ ∠A=(2x+4)

o

=(2×33+4)

o

=70

o

⇒ ∠B=(y+3)

2

=(50+3)

o

=53

o

⇒ ∠C=(2y+10)

o

=(2×50+10)

o

=110

o

⇒ ∠D=(4x−5)

o

=(4×33−5)

o

=127

o

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