Question

ABCD is a cyclic quadrilateral,if angle BAC=50°and angle DBC=60°, then find angle BCD​

Answer 1

your answer dear

Given :- angle BAC = 50° and angle DBC = 60°
To find :- angle BCD.
Solution :- 

angle BAC = angle CDB [Angles on the same segment of a circle are equal]

angle CDB = 50°

In triangle BCD,

angle BCD + angle CDB + angle DBC = 180° [Angle sum property of a triangle]

angle BCD + 50° + 60° = 180°
angle BCD + 110° = 180°
angle BCD = 180° - 110°
angle BCD = 70° ANSWER
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HOPE IT HELPS YOU....

Answer 2

Answer:

∠BCD = 70°.

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