Question

Abcd is a cyclic quadrilateral if angle bac is equals to 50 degree and angle dbc is equals to 60 degree then find angle bcd

Answer 1

Given :- angle BAC = 50° and angle DBC = 60°

To find :- angle BCD.

Solution :-

angle BAC = angle CDB [Angles on the same segment of a circle are equal]

angle CDB = 50°

In triangle BCD,

angle BCD + angle CDB + angle DBC = 180° [Angle sum property of a triangle]

angle BCD + 50° + 60° = 180°

angle BCD + 110° = 180°

angle BCD = 180° - 110°

angle BCD = 70° ANSWER

$\huge \boxed{hope \: it \: helps \: u}$

Answer 2

Given :- angle BAC = 50° and angle DBC = 60°

To find :- angle BCD.

Solution :-

angle BAC = angle CDB [Angles on the same segment of a circle are equal]

angle CDB = 50°

In triangle BCD,

angle BCD + angle CDB + angle DBC = 180° [Angle sum property of a triangle]

angle BCD + 50° + 60° = 180°

angle BCD + 110° = 180°

angle BCD = 180° - 110°

angle BCD = 70°