ABCD is a cyclic quadrilateral,if angleBCD = 110° and angleABD = 50° ,find angleADB
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I hope it's helpful
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darsh2003:
u sure its correct?
yes but of u want to check add all the degrees of answer
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Here,
BCD =110°
ABD=50°
sum of a tri = 180°
BCD+ ABD+ ADB =180°
110°+ 50° +ADB =180°
160°+ ADB= 180°
ADB =180° - 160°
ADB = 20°
BCD =110°
ABD=50°
sum of a tri = 180°
BCD+ ABD+ ADB =180°
110°+ 50° +ADB =180°
160°+ ADB= 180°
ADB =180° - 160°
ADB = 20°
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