abcd is a cyclic quadrilateral in a circle with centre o. od║bc,∠dab=68°.find ∠bcd, ∠bod, ∠obd, ∠dbc
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Step-by-step explanation:
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Answer:
The correct answer to the given question regarding the angles of given cyclic quadrilateral is as follows:
- ∠BOD = 136°
- ∠BCD = 112°
- ∠OBD = 22°
- ∠DBC = 22°
Step-by-step explanation:
As per the question,
Given:
- ABCD is the cyclic quadrilateral with O as it's centre.
- OD ║ BC
- ∠ DAB = 68°
To find:
- ∠BCD
- ∠BOD
- ∠OBD
- ∠DBC
In the cyclic quadrilateral ABCD,
Since, the angle by an arc at the centre is twice the angle on the circumference of the circle.
∠BOD = ∠BAD
∠BOD = 2 X 68°
∠BOD = 136°
∠BCD = x reflex ∠BOD
∠BCD = (360° - 136°)
∠BCD =224° X
∠BCD = 112°
As per the angle sum property,
∠OBD + ∠ODB +∠BOD = 180°
2 X ∠OBD = 180° - ∠BOD
Here, ∠OBD = ∠ODB since OD = OB
∠OBD = 22°
Since, OD is parallel to BC
In the alternate angles, the transversal is perpendicular to the parallel lines.
So, ∠BOD + ∠OBC = 180°
∠OBC = 180° - 136° = 44°
Since ∠OBD +∠DBC = ∠OBC = 44°
∠DBC = 44° - 22° = 22°
∠DBC = 22°
Therefore the required angles are found to be:
- ∠BOD = 136°
- ∠BCD = 112°
- ∠OBD = 22°
- ∠DBC = 22°
To learn more about cyclic quadrilaterals from the given links.
https://brainly.in/question/747324
https://brainly.in/question/38169
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