Abcd is a cyclic quadrilateral in which A = 75 degree and B = 100 degree, than angle C minus angle D = ?
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Answer:
Answer Is 25°
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Given:
Angle A=75°
Angle B=100°
To find:
Angle C-Angle D
Solution:
The required difference is 25°.
We can calculate the difference by obtaining the values of angles C and D.
Since ABCD is cyclic, angles A and C and angles B and D are supplementary.
So, angle A+angle C=180°
Using the values, we get
75°+angle C=180°
Angle C=180°-75°=105°
Similarly, angle B+angle D=180°.
100°+angle D=180°
Angle D=180°-100°
Angle D=80°
Now, the required difference=Angle C-angle D
=105°-80°
=25°
Therefore, the required difference is 25°.
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