Question

ABCD is a cyclic quadrilateral in which AB=15cm and Bc= 12 cm
, CD= 10 cm. if AC bisects BD then what is the measure of AD. ​

Answer 1

Answer:18

Step-by-step explanation:

Answer 2

AD = 12 cm

Step-by-step explanation:

ABCD is a cyclic quadrilateral in which AB=15cm

BC = 12 cm

CD = 10 cm

then

in triangle APD and triangle CPB

$\angle DAP = \angle CBP$

(angle in the same segment )

AP = PC  (as AC bisects BD )

$\angle APD = \angle BPC$

(vertical opposite angle )

then

$\bigtriangleup APD \cong\bigtriangleup CPB$

by ASA congruency rule

therefore

AD = BC (by CPCT )

hence , AD = BC = 12 cm

#Learn more:

ABCD in a cyclic quadrilateral BD bisects AC. AB = 10, AD = 12, DC = 11. Determine BC

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