ABCD is a cyclic quadrilateral in which AB =16.5cms, BC = x cms,CD=11cms,AD=19.8cms and BD is bisected by AC at O . what is the value of X ?
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Given:
AB =16.5 cm,
BC = x cm,
CD=11 cm,
AD=19.8 cm
To Find:
value of X
Solution:
1) the Quadrilateral given in the question is a cyclic quadrilateral and one diagonal bisects the other so by the property of the cyclic quadrilateral we have
AB × BC = CD × DA
2) by putting the value of the term in the above equation we get:
- 16.5 × x = 11 × 19.8
- x = 11 × 19.8 / 16.5
- x = 88 / 5
- x = 17.6
value of X = 17.6 cm
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