Math, asked by vanishwaryam0ika, 1 year ago

ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If angle DBC=550 and angle BAC=450 ,FIND ANGLE BCD. (NOTE:I NEED THE ANSWER FAST! PLEASE, THE CORRECT ANSWER..)

Answers

Answered by dainvincible1
10

given that ∠CAD = ∠DBC = 55     (Since angles in the same segment)

∠DAB = ∠CAD + ∠BAC

         = 55 + 45

         = 100

similarly ∠DAB + ∠BCD = 180   (Opposite angle of a cyclic quadilateral)

 => ∠BCD = 180 - ∠DAB

                = 180 - 100

=> ∠BCD = 80

Attachments:
Answered by noraizyt3
0

Answer:

Here You Go!!! , CHAPTER CIRCLE

Step-by-step explanation:

given that ∠CAD = ∠DBC = 55     (Since angles in the same segment)

∠DAB = ∠CAD + ∠BAC

        = 55 + 45

        = 100

similarly ∠DAB + ∠BCD = 180   (Opposite angle of a cyclic quadrilateral)

=> ∠BCD = 180 - ∠DAB

               = 180 - 100

=> ∠BCD = 80

Similar questions