ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If angle DBC=550 and angle BAC=450 ,FIND ANGLE BCD. (NOTE:I NEED THE ANSWER FAST! PLEASE, THE CORRECT ANSWER..)
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given that ∠CAD = ∠DBC = 55 (Since angles in the same segment)
∠DAB = ∠CAD + ∠BAC
= 55 + 45
= 100
similarly ∠DAB + ∠BCD = 180 (Opposite angle of a cyclic quadilateral)
=> ∠BCD = 180 - ∠DAB
= 180 - 100
=> ∠BCD = 80
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Answer:
Here You Go!!! , CHAPTER CIRCLE
Step-by-step explanation:
given that ∠CAD = ∠DBC = 55 (Since angles in the same segment)
∠DAB = ∠CAD + ∠BAC
= 55 + 45
= 100
similarly ∠DAB + ∠BCD = 180 (Opposite angle of a cyclic quadrilateral)
=> ∠BCD = 180 - ∠DAB
= 180 - 100
=> ∠BCD = 80
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