Question

ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If < DBC= 55 and <

BCD. ​

Answer 1

Answer:

Given that ∠CAD = ∠DBC = 55 (Since angles in the same segment)

∠DAB = ∠CAD + ∠BAC

= 55 + 45

= 100

similarly ∠DAB + ∠BCD = 180 (Opposite angle of a cyclic quadilateral)

=> ∠BCD = 180 - ∠DAB

= 180 - 100

=> ∠BCD = 80