ABCD is a cyclic quadrilateral in which AD and BC
are parallel. If ZABC = 72°, the mZBCD ?
(a) 162° (b) 18° (©) 108° (d) 72°
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Answer:
72+72+x+x= 360
2x= 360-144
2x=216
x= 216/2
x=108
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