ABCD is a cyclic quadrilateral such that A=4y+20,B=3y-5,C=4x and D=7x+5 find the four angles
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Answer:
x=25,y=15
Step-by-step explanation:
A+C = 180
B+D = 180
4y+20+4x=180
x+y=40 (1)
3y-5+7x+5=180
7x+3y=180 (2)
solve (1) &(2) by substitution:
-7x-7y=-280
7x+3y=180
-4y=-100
y=25
x+25=40
x=15
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