Math, asked by junghyunie16, 7 months ago

ABCD is a cyclic quadrilateral such that AB||DC. If ACD = 35° and DBC =72°, calculate the sizes of the angles of the trapezium.

Can someone please help me ASAP.....

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Answered by sahil709124

16

PLs give me brainly marks

Answer:

∠BCA = ∠ADB = 40° [angles in same segment of a circle are equal]

Now, ∠BCD = 70° + 40° = 110°

∠DAB + ∠BCD = 180°

∠DAB = 180° - 110°

⇒ ∠DAB = 70°

Answered by mariastephen360

0

Answer:

A

Step-by-step explanation:

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