Question

ABCD is a cyclic quadrilateral such that <A-<C =20° then find <A,<C​.it's urgent need help who Will answer I will mark as brainliest...

Answer 1

Answer:

AS WE KNOW

IN A CYCLIC QUADRILATERAL SUM OF OPPOSITE ANGLES = 180°

NOW

ACCORDING TO QUESTION

ANGLE A- ANGLE C= 20° ----------1

ANGLE A+ANGLE C = 180° -----------2

ELIMINATE EQUATIONS BY ADDING THEM

2(ANGLE A) = 200°

ANGLE A= 100° -------PUT IN 1

ANGLE C 80°

Answer 2

Answer:

<A + <C = 180°. [ opp. angles of cyclic quad]

<A = 180°- <C --------(i)

<A -<C = 20°

<A = 20° + <C. ---------(ii)

from (i) and (ii) ,

180 - <C = 20 + <C

2<C = 180-20

2<C = 160

<C = 80 °

placing <C = 80° in eq. (ii)

<A = 20 + <C

<A = 20 +80 = 100°