abcd is a cyclic quadrilateral whose diagonals intersect at at a point e. 9f dbc =70 bac is 30 find bcd
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HERE YOU GO~
(i) GIVEN = ABCD is a cyclic quadrilateral where
/_DBC = 70°
/_BAC = 30°
(ii) TO FIND - /_BCD = ?
(iii) PROOF ->
Firstly,
/_BAC = /_BDC. [Angles in same segment]
In triangle DBC,
/_BDC + /_DBC + /_BCD = 180°
=> 30° + 70° + /_BCD = 180°
=> /_BCD = 180° - ( 70 + 30 )°
=> /_BCD = 180° - 100°
=> /_BCD = 80°.
HENCE PROVED.....
THANKS.....
@anmol
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