Question

abcd is a cyclic quadrilateral whose diagonals intersect at a point B if angle dbc=70° angle bac =30° find angle bcd furthur if ab=bc find angle ecd​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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Step-by-step explanation:

ABCD is a cyclic quadrilateral whose diagonal intersect at E.

∠CBD = ∠CAD (Angles in the same segment are equal)

∠CAD = 70°

∠BAD = ∠BAC + 2CAD = 30° +70° = 100°

∠BCD + ∠BAD = 180° (Opposite angles of a cyclic quadrilateral)

∠BCD +100° = 180°

∠BCD = 80°

In AABC,

AB=BC (Given)

∴ ∠BCA = ∠CAB (Angles opposite to equal sides of a triangle are equal)

→ ∠BCA = 30°

But ∠BCD = 80°.

→ ΔBCA + ΔACD = 80°

30° + ∠ACD = 80°

→ ∠ACD = 50°

→ ΔECD = 50°.