Question

ABCD is a cyclic quadrilateral whose side AB is the diameter of the circle through the points A,B,C,D. If,Angle ACD=130. Then find the Angle BAC​

Answer 1

Answer:40 degrees

Step-by-step explanation:

∠ACB=90  

o

 (angle subtended by the diameter of circle)

and ∠ABC is the supplementary angle of ∠ADC. (opposite angles of cyclic quadrilateral)

∴∠ABC=180−∠ADC=180−130=50  

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∠BAC=180−(∠ACB+∠ABC)

=180−50−90=40  

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