ABCD is a cyclic quadrilateral with AD Parallel BC. Prove that AB=DC
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Answered by
12
in the cyclic quadilateral ABCD
let angle ADC be x now angle ABC is 180-x
since AD is parallel to BC
therefore angle ADC+angleDAB is 180
angle DAB is 180-x
now angle DAB and ABC r equal
so AB=CD
let angle ADC be x now angle ABC is 180-x
since AD is parallel to BC
therefore angle ADC+angleDAB is 180
angle DAB is 180-x
now angle DAB and ABC r equal
so AB=CD
tisha02:
I not think it is right,Is it correct?
I think its not let me look to it again as soon as I get it right i'll edit it :)
Thank-you but make it do fast plzzzzzzzzzzzzzzz
I think its not let me look to it again as soon as I get it right i'll edit it :)
this is the right way
ok
Answered by
5
Let ADC=x
So, abc=180-x
Since ad//bc
Bcd=abc=90
Adc=bad=90
So.ab=dc
So, abc=180-x
Since ad//bc
Bcd=abc=90
Adc=bad=90
So.ab=dc
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