ABCD is a cyclic quadrilateral with ADC= 135°. Sides BA and CD produced meet at point P, sides AD and BC produced meet at Q. If P:Q =2:1 ; find angles P and Q
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x=45°...................its mistake in photo so correct value of x is 45°
2x=2×45=90°
1x=1×45=45°
so Angle P=90°
Angle Q=45°
2x=2×45=90°
1x=1×45=45°
so Angle P=90°
Angle Q=45°
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