ABCD is a cyclic quardilateral find the angle of quardilateral
Answers
Answer:
Step-by-step explanation:
AC=22cm BM=3cm2 A of ΔABC=1/2 bh =21×11×3 =33cm A of ΔABC=1/2bh=1/2×22×3 =33cm2 A quardilateral = A of ΔABC + A of ΔADC =33+33 =66cm2
Answer:
Step-by-step explanation:
AC=22cm BM=3cm2 A of ΔABC=1/2 bh =21×11×3 =33cm A of ΔABC=1/2bh=1/2×22×3 =33cm2 A quardilateral = A of ΔABC + A of ΔADC =33+33 =66cm2