Abcd is a cyclic trapezium with ab || bc . if ∠a = 105° , then other three angles are
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Let assume ABCD Is Trapezium,
where AB||CD
Angle A=105
Let's start
Angle A +Angle B=180(AB||CD AC is Trasversal,,and Angle in same side of transversal is 180°)
Here we get Angle B=75°
Similarly Angle C=105°
Angle D=75°
Hope it's Help You!!
where AB||CD
Angle A=105
Let's start
Angle A +Angle B=180(AB||CD AC is Trasversal,,and Angle in same side of transversal is 180°)
Here we get Angle B=75°
Similarly Angle C=105°
Angle D=75°
Hope it's Help You!!
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